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9x^2+61x+102=0
a = 9; b = 61; c = +102;
Δ = b2-4ac
Δ = 612-4·9·102
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-7}{2*9}=\frac{-68}{18} =-3+7/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+7}{2*9}=\frac{-54}{18} =-3 $
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